php返回json数据并输出的简单实例

这里奉上一个php解析json数据，并输出的示例，供大家参考。

折叠PHP 代码

<?php
echo '<h1>法一</h1>';
//假设以下数组是根据我们从数据库读取的数据生成的
$jarr=array('total'=>239,'row'=>array(
array('code'=>'001','name'=>'中国','addr'=>'Address 11','col4'=>'col4 data'),
array('code'=>'002','name'=>'Name 2','addr'=>'Address 12','col4'=>'col4 data'),
)
);
//法一：
$jobj=new stdclass();//实例化stdclass，这是php内置的空类，可以用来传递数据，由于json_decode后的数据是以对象数组的形式存放的，
//所以我们生成的时候也要把数据存储在对象中
foreach($jarr as $key=>$value){
$jobj->$key=$value;
}
print_r($jobj);//打印传递属性后的对象
echo '使用$jobj->row[0][\'code\']输出数组元素:'.$jobj->row[0]['code'].'<br>';
echo '编码后的json字符串：'.json_encode($jobj).'<br>';//打印编码后的json字符串
echo '<hr>';
//法二：
echo '<h1>法二</h1>';
echo '编码后的json字符串：';
echo $str=json_encode($jarr);//将数组进行json编码
echo '<br>';
$arr=json_decode($str);//再进行json解码
print_r($arr);//打印解码后的数组，数据存储在对象数组中
echo '使用$arr->row[0]->code输出数组元素:'.$arr->row[0]->code;
?>

另外一个简单的例子，非常直观。

折叠PHP 代码

<?php
$json='[{"name":"qqdeliver","count":198,"average":119.8889},{"name":"load","count":259612,"average":141.9379},{"name":"gate","count":22480,"average":9.2209},{"name":"interact","count":40165,"average":429.3583},{"name":"save","count":2097845,"average":180.6606},{"name":"login","count":29239,"average":322.0906},{"name":"neighbour","count":24777,"average":368.9143},{"name":"updatesave","count":842358,"average":75.1193},{"name":"promotion","count":69417,"average":37.7616},{"name":"activity","count":22978,"average":5.4393},{"name":"message","count":49590,"average":172.3676},{"name":"admin","count":155,"average":750.3032},{"name":"qqpay","count":3078,"average":79.4916},{"name":"alliance","count":54091,"average":120.0409},{"name":"updates","count":189196,"average":54.6144},{"name":"friend","count":26259,"average":101.0704},{"name":"attack","count":8146,"average":205.2529}]';
$obj=json_decode($json);
//print_r($obj);
foreach ( $obj as $unit ){
echo $unit->name.'<br>';
}
?>

Tags： php json